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Question

Prove that [a,b+c,d]=[abd]+[acd]

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Solution

[a.b+c.d]
=a.{(b+c)×d}
={a.(b+c)}×(a.d)
=(a.b+a.c)×(a.d)
=a.b×(a.d)+a.c×(a.d)
=a.(b×d)+a.(c×d)
=[abd]+[acd]

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