prove that (root3 + 1)(3 - cot30degrees) = tancube60degrees - 2sin60dgrees

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2 c o s \frac{π}{13} c o s \frac{9 π}{13} + c o s \frac{3 π}{13} + c o s \frac{5 π}{13} = 0

2 cos \frac{π}{13} cos \frac{9 π}{13} + cos \frac{3 π}{13} + cos \frac{5 π}{13} = 0

sec θ = 13

sin θ = \frac{12}{13}

5 s e c θ = 13

s i n θ = \frac{12}{13}

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