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Question

Prove that secA(1sinA)(secA+tanA)=1

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Solution

secA(1sinA)(secA+tanA)=1
1cosA(1sinA)(1cosA+sinAcosA)
1cos2A(1sinA)(1+sinA)1sin2Acos2A=cos2Acos2A=1

1213156_1415955_ans_c9dd26ea0c59432987b4dbd5cf44edc2.jpg

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