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Question
Prove that: ∼(p⇔q)≡∼p⇔q.
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Solution
To Prove:∼(p⇔q)≡∼p⇔q
Solution:
p q ∼q p⇔q ∼(p⇔q) ∼p⇔q T T F T F F T F F F T T F T T F T T F F T T F F
Hence, from the truth table, ∼(p⇔q)≡∼p⇔q.
∼(p⇔q)≡∼p⇔q
Solution:
Hence, from the truth table, ∼(p⇔q)≡∼p⇔q.
| p | q | ∼q | p⇔q | ∼(p⇔q) | ∼p⇔q |
| T | T | F | T | F | F |
| T | F | F | F | T | T |
| F | T | T | F | T | T |
| F | F | T | T | F | F |
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