Prove that sin 2(π/8 + A/2) - sin2 (π/8 - A/2) = sin π/4 * sin A
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Solution
Using the formula sin2A-sin2B = sin (A+B)sin(A-B) We get , sin 2(π/8 + A/2) - sin2 (π/8 - A/2)= sin (π/8+A/2 +π/8 -A/2) * sin (π/8+A/2-π/8+A/2) =sin(π/4)sinA Hence proved