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Question

Prove that
sin 2(π/8 + A/2) - sin2 (π/8 - A/2) = sin π/4 * sin A

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Solution

Using the formula
sin2A-sin2B = sin (A+B)sin(A-B)
We get ,
sin 2(π/8 + A/2) - sin2 (π/8 - A/2)= sin (π/8+A/2 +π/8 -A/2) * sin (π/8+A/2-π/8+A/2)
=sin(π/4)sinA
Hence proved

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