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Byju's Answer
Standard X
Mathematics
Range of Trigonometric Ratios from 0 to 90 Degrees
Prove that: ...
Question
Prove that:
sin
π
15
+
sin
4
π
15
−
sin
11
π
15
−
sin
14
15
=
0
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Solution
L
H
S
=
s
i
n
π
15
+
s
i
n
4
π
15
−
s
i
n
11
π
15
−
s
i
n
14
π
15
L
H
S
=
s
i
n
π
15
+
s
i
n
4
π
15
−
s
i
n
(
π
−
11
π
15
)
−
s
i
n
(
π
−
14
π
15
)
[Since
s
i
n
(
π
−
x
)
=
s
i
n
x
]
L
H
S
=
s
i
n
π
15
+
s
i
n
4
π
15
−
s
i
n
4
π
15
−
s
i
n
π
15
L
H
S
=
0.
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0
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Q.
Prove that
sin
π
15
+
sin
4
π
15
−
sin
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π
15
−
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If
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