Prove that:
cot2π6+cosec5π6+3tan2π6=6
We have
L.H.S = cot2π6+cosec5π6+3tan2π6= 6
Now cosec 5π6 = cosec (π−π6) = cosec π6 = 2
∴cot2π6+cosec5π6+3tan2π6
= (√3)2+2+3×(1√3)2
= 3+2+3 ×13
= 5+1 = 6 = R.H.S