Let z1=x1+iy1 and z2=x2+iy2 be two complex numbers.
First suppose z1,z2 are conjugate of each other. Then,
z2=¯z1=x1+iy1
Hence z1+z2=z1+¯z1=2x1, which is real and z1z2=z1¯z1=(x1+iy1)(x1−iy1)=x12+y12, which is also real.
Thus sum z1+z2 and product z1z2 are real when z1 and z2 are conjugate complex.
Now let the sum z1+z2 and product z1z2 be real. We have z1+z2=(x1+x2)+i(y1+y2)
and z1z2=x1x2−y1y2+i(x1y2+x2y1)
Since z1+z2 and z1z2 are both real, we must have y1+y2=0 and x1y2+x2+y1=0
These give y2=−y1 and x2=x1.
Hence z2=x2+iy2=x1−iy1=¯z1, that is, z1 and z2 are conjugate complex.