Prove that -a-b-b-c-c-a-2-a-b-c-

[ a + b b + cc + a] = [((a+b).(b+ c)) × (c +a )] #160; = ((a.b)+(a .c) + (b.b) + (b.c)) × (c + a) #160; = (a.b) ×c #160; + (a.c)× c + ( b. ...

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Many One Function

Prove that ...

Question

Prove that $[\to a + \to b, \to b + \to c, \to c + \to a] = 2 [\to a, \to b, \to c]$

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\to a, \to b, \to c

\to a \times \to b = \to c, \to b \times \to c = \to a, \to c \times \to a = \to b

| \to a | = | \to b | = | \to c |

\to A

\to B

\to C

| \to B | =

\to C |

[(\to A + \to B) \times (\to A + \to C)] \times (\to B \times \to C) . (\to B + \to C) = 0

\to a + \to b + \to c = 0

\to a \times \to b = \to b \times \to c = \to c \times \to a

\to a, \to b, \to c

(\to a + \to b) \times (\to a - \to b) + (\to b + \to c) \times (\to b - \to c) + (\to c + \to a) \times (\to c - \to a) =

[\to a + 2 \to b - \to c, \to a - \to b, \to a - \to b - \to c] =

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