Prove that :- (x-y)3= x3 ? y3 -3x2y + 3xy2

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Solution

Dear Student,
$(x - y)^{3} = (x - y)^{2} (x - y) = (x^{2} - 2 x y + y^{2}) (x - y) [(a - b)^{2} = a^{2} + b^{2} - 2 a b] = (x^{2} - 2 x y + y^{2}) (x - y) = x^{3} - x^{2} y - 2 x^{2} y + 2 x y^{2} + x y^{2} - y^{3} = x^{3} - 3 x^{2} y + 3 x y^{2} - y^{3}$
Regards

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