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General Solutions of (sin theta)^2 = (sin alpha)^2 , (cos theta)^2 = (cos alpha)^2 , (tan theta)^2 = (tan alpha)^2

Prove the fol...

Question

Prove the following:-

Cos4x=1-8sin^2xcos^2x

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Solution

you can solve

cos4x as

cos2(2x) =1-2sin²(2x)
=1-2(2sinx . cosx)²
{ sin2x = 2sinx. cosx}
=1-2(4sin²x.cos²x)
=1-8sin²x.cos²x

LHS=RHS

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General Solutions of (sin theta)^2 = (sin alpha)^2 , (cos theta)^2 = (cos alpha)^2 , (tan theta)^2 = (tan alpha)^2

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