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Question

Prove the following identity 1cot Acsc A+1sinA=cot A

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Solution

1(cscAcotA)×(cscA+cotA)(cscA+cotA)=[cscA+cotA](cscA2cot2A=1)

=cscAcotA+1sinA

=1sinAcotA+1sinA

=cotA

Hence proved.

1063118_1038357_ans_d1ea3b797cba4f7ebb36d45bd324761b.jpg

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