$[P t (N H_{3})_{6}] C l_{4}$ complex gives :

4 ions

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3 ions

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5 ions

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2 ions

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Solution

The correct option is C 5 ions
In $[P t (N H_{3})_{6}] C l_{4}$ [hexamine platinum(IV) chloride]. It gives 4 $C l^{-}$ ions (free ions) and one cation $[P t (N H_{3})_{6}]^{4 +}$ in the solution. $N H_{3}$ will not dissociate because it is inside the coordination sphere.Hence it has total 5 ions in the solution.

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