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Conductance of Electrolytic Solution

PtCl4.6H2O on...

Question

$P t C l_{4} .6 H_{2} O$ on reaction with $A g N O_{3}$ forms $2$ moles of $A g C l$ (whit ppt) per mol of the $P t C l_{4} .6 H_{2} O$ . The complex exists as $[P t C l_{2} (H_{2} O)_{4}] C l_{2} . 2 H_{2} O$ .
If true enter 1, else enter 0.

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Solution

$P t C l_{4} .6 H_{2} O$ on reaction with $A g N O_{3}$ forms $2$ moles of $A g C l$ (whit ppt) per mol of the $P t C l_{4} .6 H_{2} O$ .
Only chloride ions that are present outside react with $A g N O_{3}$ to give white ppt. of $A g C l$ . Since 2 moles are produces, this means 2 $C l$ atoms are present outside.
Therefore, the complex exists as $[P t C l_{2} (H_{2} O)_{4}] C l_{2} \cdot 2 H_{2} O$ .
Hence, the correct answer is 1.

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