Question

Pure inductors each of inductance $3H$ are connected as shown. The equivalent induction of the circuit is

• A. $1H$
• B. $2H$
• C. $3H$
• D. $9H$

Answer 1

The correct option is A $1H$

$\frac{1}{L_{eq}}=\frac{1}{3H}+\frac{1}{3H}+\frac{1}{3H}$

$l_{eq}=1H$

Option A is correct,