Question

Pure samples of water always yield $88.89\%$ of oxygen and $11.11\%$ of hydrogen, by mass. This can be explained by using the law of:

• A. Conservation of mass
• B. Constant proportions
• C. Multiple proportions
• D. Reciprocal proportions

Answer 1

The correct option is B Constant proportions

The law of definite proportions states that a given chemical compound always contains its component elements in a fixed ratio by mass and does not depend on its source and the method of preparation.
Therefore, the ratio of $H:O$ in water = $11.11:88.89=1:8$ which will be constant in any sample of water irrespective of the source and the method of preparation.