Pyrolusite in MnO2 is used to prepare KMnO4- Steps are MnO2I-MnO2-4II-MnO-4-I and II are-

The correct option is A Fuse with KOH/air, electrolytic oxidation 2MnO_2+4KOH+O_2→ 2K_2MnO_4+2H_2O #160; #160;— #160; Step I MnO^2 _4Electroly ...

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Byju's Answer

Standard XII

Chemistry

Potassium Permanganate

Pyrolusite in...

Question

Pyrolusite in $M n O_{2}$ is used to prepare $K M n O_{4}$ .
Steps are $M n O_{2} I ⟶ M n O_{4}^{2 -} I I ⟶ M n O_{4}^{-}$ .
I and II are:

Fuse with KOH/air, electrolytic oxidation

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Fuse with KOH/air, electrolytic reduction

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Fuse with conc

H N O_{3}

/air, electrolytic reduction

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All of the above

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Solution

The correct option is A Fuse with KOH/air, electrolytic oxidation
$2 M n O_{2} + 4 K O H + O_{2} \to 2 K_{2} M n O_{4} + 2 H_{2} O$ ---- Step I

$M n O_{4}^{2 -} E l e c t r o l y t i c o x i d a t i o n ⟶ M n O_{4}^{-}$ ---- Step II

So, A is the correct option.

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Similar questions

Q. Pyrolusite is

M n O_{2}

used to prepare

K M n O_{4}

. Steps are

M n O_{2} I \to M n O_{4}^{2 -} I I \to M n O_{4}^{-}

Steps I and II are:

Q. Pyrolusite in

M n O_{2}

is used to prepare

K M n O_{4}

.
Steps are :

M n O_{2} I \to M n O_{4}^{2 -} + M n O_{4}^{-}

Q. Pyrolusite is

M n O_{2}

used to prepare

K m N O_{4}

steps are

M n O_{2} i \to M n O_{4}^{2 -} i i \to M n O_{4}^{-}

. steps i and ii are respectively

Q. Pyrolusite in

M n O_{2}

is used to prepare

K M n O_{4}

. Steps are

M n O_{2} I \to M n O_{4}^{2 -} I I - \to M n O_{4}^{-}

I

and

I I

are:

Q. Pyrolusite is

M n O_{2}

used to prepare

K M n O_{4}

. Steps are:

M n O_{2} I \to M n O_{2}^{2 -} I I - \to M n O_{4}^{-}

Steps

I

and

I I

are respectively:

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Pyrolusite in MnO2 is used to prepare KMnO4. Steps are MnO2I⟶MnO2−4II⟶MnO−4.I and II are:

The correct option is A Fuse with KOH/air, electrolytic oxidation2MnO2+4KOH+O2→2K2MnO4+2H2O ---- Step IMnO2−4Electrolyticoxidation⟶MnO−4 ---- Step II So, A is the correct option.

Pyrolusite in $M n O_{2}$ is used to prepare $K M n O_{4}$ .
Steps are $M n O_{2} I ⟶ M n O_{4}^{2 -} I I ⟶ M n O_{4}^{-}$ .
I and II are:

The correct option is A Fuse with KOH/air, electrolytic oxidation
$2 M n O_{2} + 4 K O H + O_{2} \to 2 K_{2} M n O_{4} + 2 H_{2} O$ ---- Step I

$M n O_{4}^{2 -} E l e c t r o l y t i c o x i d a t i o n ⟶ M n O_{4}^{-}$ ---- Step II

So, A is the correct option.