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Zero Order Reaction

Q 10/58 The v...

Question

{ Q }10/58 The value of }K_c for the dissociation reaction is }}{H_2(g)=2H(g) is }1.2×10^{-43}} This equilibrium mixture contains

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K_{c}

H_{2} (g) ⇌ 2 H (g)

2.1 \times 10^{- 42}

N_{2} (g) + 2 H_{2} (g) \Leftrightarrow N_{2} H_{4} (g)

K_{c} = 7.4 \times 10^{- 26}

N_{2} O_{4} (g) ⇌ 2 N O_{2} (g)

N_{2} O_{4}

N O_{2}

4.8 \times 10^{- 2}

1.2 \times 10^{- 2} m o l L^{- 1}

K_{c}

K_{p}

2 H_{2} S (g) \Leftrightarrow 2 H_{2} (g) + S_{2} (g)

1.2 \times 10^{- 2}

1065^{\circ} C

K_{C}

k_{p}

2 A B (g) \Leftrightarrow 2 A (g) + B_{2} (g)

1.2 \times 10^{- 2}

1065^{\circ} C

k_{c}

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