Question

Q.2. A coin is tossed 1000 with the following frequencies:
Head : 460, Tail : 540
Compute the probability for each event.

Answer 1

Dear student
$$\begin{gathered} \mathrm{Given}:\mathrm{a}\mathrm{coin}\mathrm{is}\mathrm{tossed}1000\mathrm{times}\mathrm{with}\mathrm{the}\mathrm{following}\mathrm{frequencies}: \\ \mathrm{Head}=460\mathrm{and}\mathrm{Tail}=540 \\ \mathrm{So},\mathrm{n}\left(\mathrm{S}\right)=1000 \\ \mathrm{We}\mathrm{know}\mathrm{P}\left(\mathrm{E}\right)=\frac{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{desired}\mathrm{events}\mathrm{n}\left(\mathrm{E}\right)}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{events}\mathrm{n}\left(\mathrm{S}\right)} \\ 1)\mathrm{The}\mathrm{probability}\mathrm{of}\mathrm{getting}\mathrm{a}\mathrm{head}=\frac{460}{1000}=\frac{23}{50} \\ 1)\mathrm{The}\mathrm{probability}\mathrm{of}\mathrm{getting}\mathrm{a}\mathrm{tail}=\frac{540}{1000}=\frac{27}{50} \end{gathered}$$
Regards