Q- 20 g of CaCO3 nbsp-is reacted with 20g of HCl- Find amount of CO2 nbsp-formed- Identify the limiting reagent- Calculate the amount of substance which remained unreacted- nbsp- nbsp-

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Standard XII

Chemistry

Heat of Formation

Q. 20 g of Ca...

Question

Q. 20 g of CaC $O_{3}$ is reacted with 20g of HCl. Find amount of C $O_{2}$ formed. Identify the limiting reagent. Calculate the amount of substance which remained unreacted.

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Solution

Dear Student,

According to the given balanced equation, the stiochiometry suggests that 1 mol of CaCO₃ requires to evolve 1 mol of CO₂.
But in the reaction when 1 mol of CaCO₃reacts with 2 mol of HCl it give 1 mol of CO₂. Or can be said as that 100 g of CaCO₃ reacts with 73 g of HCl to produce 44 g of CO₂.
So, 20 g of CaCO₃ will react with $\frac{73}{100} \times 20 = 14.6 g o f H C l$
So the limiting reagent is CaCO₃, and the number of moles of CaCO₃ consumed will be 20/100 = 0.2 moles
and according stiochiometry 0.2 mol of CO₂ will be produced = 0.2 x 44 = 8.8 g

So, the amount of CO₂ will be produced is 8.8 g

Regards.

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Q. 20 g of CaCO3 is reacted with 20g of HCl. Find amount of CO2 formed. Identify the limiting reagent. Calculate the amount of substance which remained unreacted.

Q. 20 g of CaC $O_{3}$ is reacted with 20g of HCl. Find amount of C $O_{2}$ formed. Identify the limiting reagent. Calculate the amount of substance which remained unreacted.