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Intensity Amplitude Relationship

Q.9. The appa...

Question

Q.9. The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What the actual depth of the liquid in the tank?

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Solution

Dear student,
$R e f r a c t i v e i n d e x = \frac{R e a l d e p t h}{A p p a r e n t d e p t h} R e a l d e p t h = R e f r a c t i v e i n d e x \times A p p a r e n t d e p t h R e a l d e p t h = 1.3 \times 7.7 R e a l d e p t h = 10.01 c m$

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