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Q ​A mass 'm' moves with a velocity 'v' and collides inelastically with another identical mass at rest.
After collision the first mass moves with velocity v3 in a direction perpendicular to the initial direction
of motion. Find the speed of the second mass after collision :1.2v32. v33. v234. The situation of the problem is not possible without external impulse

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Solution

Dear student

Applying conservation of momentum along X axisInitial momentum along X axis is Pi=mvFinal momentum along X axis Pi=mvxmvx=mvvx=vApplying conservation of momentum along X axis0=mv3-mvymv3-mvy=0vY=v3net speedv=v2x+v2y=v2+v23=2v3Regards

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