Q A microsocpe is provided with a main scale graduated with 20 divisions in 1 cm and a vernier scale with 50 divisions on it of length same as of 49 divisions of main scale. Find the least count of the microscope.

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Solution

Dear Student
$V a l u e o f 1 d i v i s i o n o f m a i n s c a l e = \frac{1}{20} = 0.05 c m L e a s t C o u n t = \frac{V a l u e o f 1 d i v i s i o n o f m a i n s c a l e}{T o t a l n u m b e r o f d i v i s i o n s o n v e r n i e r s c a l e} = \frac{0.05}{50} = 0.001 c m$
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Q ​A microsocpe is provided with a main scale graduated with 20 divisions in 1 cm and a vernier scale with 50 divisions on it of length same as of 49 divisions of main scale. Find the least count of the microscope.

Dear Student Value of 1 division of main scale =120=0.05 cmLeast Count = Value of 1 division of main scale Total number of divisions on vernier scale=0.0550=0.001 cm Regards

Q A microsocpe is provided with a main scale graduated with 20 divisions in 1 cm and a vernier scale with 50 divisions on it of length same as of 49 divisions of main scale. Find the least count of the microscope.

Dear Student
$V a l u e o f 1 d i v i s i o n o f m a i n s c a l e = \frac{1}{20} = 0.05 c m L e a s t C o u n t = \frac{V a l u e o f 1 d i v i s i o n o f m a i n s c a l e}{T o t a l n u m b e r o f d i v i s i o n s o n v e r n i e r s c a l e} = \frac{0.05}{50} = 0.001 c m$
Regards