Q) A Women weighing 50 kgf stands on a weighing machine placed in a lift. What will be the reading of the machine when the lift is
a) moving upward
b) moving downward with uniform velocity of 10ms^-1

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Solution

$(a) Apparent weight : W' = W (1 + \frac{a}{g}) As a is positive, the reading of machine increases while moving up . (b) Apparent weight : W' = W (1 - \frac{a}{g}) - - > moving down Here, a = 0 since the lift is moving with uniform velocity . Hence, W' = W The reading of machine remains same, that is, 50 kgf only$

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Q) A Women weighing 50 kgf stands on a weighing machine placed in a lift. What will be the reading of the machine when the lift is a) moving upward b) moving downward with uniform velocity of 10ms​-1

(a)Apparent weight:W'=W1+agAs a is positive, the reading of machine increases while moving up.(b)Apparent weight:W'=W1-ag --> moving downHere, a = 0 since the lift is moving with uniform velocity.Hence, W'=WThe reading of machine remains same, that is, 50 kgf only

Q) A Women weighing 50 kgf stands on a weighing machine placed in a lift. What will be the reading of the machine when the lift is
a) moving upward
b) moving downward with uniform velocity of 10ms^-1