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Equilibrium Constant and Standard Free Energy Change

qAB=2kJ/molΔU...

Question

$q_{A B} = 2 k J / m o l Δ U_{B C} = - 5 k J / m o l W_{A B} = - 5 k J / m o l W_{C A} = 3 k J / m o l$
Heat absorbed by the system during process CA is:

$- 5 k J m o l^{- 1}$

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$+ 5 k J m o l^{- 1}$

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$18 k J m o l^{- 1}$

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$- 18 k J m o l^{- 1}$

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Solution

The correct option is B
$+ 5 k J m o l^{- 1}$

$Δ U_{A B} = q_{A B} + W_{A B} = 2 + (- 5) = - 3 k J / m o l$

$Δ U_{B C} = - 5 k J / m o l$

For cyclic process, $Δ U = 0$

$Δ U_{A B} + Δ U_{B C} + Δ U_{C A} = 0$

$Δ U_{C A} = - Δ U_{A B} - Δ U_{B C}$

$Δ U_{C A} = - (- 3) - (- 5) = 8 k J / m o l$

$Δ U_{C A} = q_{C A} + W_{C A}$

$8 = q_{C A} + 3$

$q_{C A} = + 5 k J / m o l$

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