Q Subtract reciprocal of 11/7 from reciprocal of 16/3.

Open in App

Solution

$Reciprocal of \frac{11}{7} = \frac{7}{11} Reciprocal of \frac{16}{3} = \frac{3}{16} Now, \frac{3}{16} - \frac{7}{11} = \frac{33 - 112}{176} = - \frac{79}{176}$

Suggest Corrections

Similar questions

16^{- 7}

{(\frac{2}{3})}^{- 4}

\frac{7}{11}

Product of $\frac{7}{6}$ and reciprocal of $\frac{11}{66}$ is __________.

\frac{6}{13}

\frac{- 7}{16}

\frac{6}{13}

\frac{- 7}{16}

Join BYJU'S Learning Program