Write the reciprocal of each of the following:
(i) $16^{- 7}$
(ii) ${(\frac{2}{3})}^{- 4}$

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Solution

(i) ${(16)}^{- 7}$
$= {(\frac{1}{16})}^{7}$
reciprocal of ${(16)}^{- 7} = {(\frac{16}{1})}^{7} = {(16)}^{7}$
(ii) ${(\frac{2}{3})}^{- 4} = {(\frac{3}{2})}^{4}$
Reciprocal of ${(\frac{2}{3})}^{- 4} = {(\frac{2}{3})}^{4}$

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