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Byju's Answer
Standard XII
Physics
Dimensional Analysis
Q. The dimens...
Question
Q. The dimensional formula for thermal resistance is
1
.
M
-
1
L
-
2
T
3
θ
2
.
M
-
1
L
-
2
T
-
3
θ
3
.
M
L
2
T
-
2
θ
4
.
M
L
2
T
2
θ
-
1
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Solution
Dear Student ,
The dimensional formula for thermal conductivity is =
M
L
T
-
3
θ
-
1
So the dimension of thermal resistance is =
M
-
1
L
-
2
T
-
3
θ
Regards
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Q.
Match the following.
List I
List II
A.
Angular momentum
1.
[
M
−
1
L
2
T
−
2
]
B.
Torque
2.
[
M
1
T
−
2
]
C.
Gravitational constant
3.
[
M
1
L
2
T
−
2
]
D.
Tension
4.
M
1
L
2
T
−
1
]
Q.
Let
[
ε
0
]
denote the dimensional formula of the permittivity of the vaccum and
[
μ
0
]
denote the permeability of the vacuum. If
M
= mass,
L
=
length,
T
=
time and
I
=
electric current, then