Q. The ratio of a two-digit natural number to a number formed by reversing its digits is $13 : 31$ . The number of such pairs is:

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More than 3

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Solution

The correct option is C
3
Let the two digit number $= a b \to 10 a + b$
By reversing, ba $\to 10 b + a$
Now ab: ba $= 13 : 31$
So, $31 (10 a + b) = 13 (10 b + a) \to a : b = 1 : 3$
Possible numbers are $13, 26,$ and $39$ .

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Q. The ratio of a two-digit natural number to a number formed by reversing its digits is 13:31. The number of such pairs is:

The correct option is C 3Let the two digit number =ab→10a+b By reversing, ba →10b+a Now ab: ba =13:31 So, 31(10a+b)=13(10b+a)→a:b=1:3 Possible numbers are 13,26, and 39.

Q. The ratio of a two-digit natural number to a number formed by reversing its digits is $13 : 31$ . The number of such pairs is:

The correct option is C
3
Let the two digit number $= a b \to 10 a + b$
By reversing, ba $\to 10 b + a$
Now ab: ba $= 13 : 31$
So, $31 (10 a + b) = 13 (10 b + a) \to a : b = 1 : 3$
Possible numbers are $13, 26,$ and $39$ .