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Anionic Radius

Q.xliv. In Ca...

Question

Q.xliv. In $C a F_{2}$ crystal $C a^{2 +}$ ion are present fcc arrangement. Calculate the number of $F^{-}$ ion in the unit cell:

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Solution

Dear Student,

Given that Ca² ⁺ ion are in the fcc arrangement ,
So there are 4 octahedral voids present in the fcc lattice. [8x1/8+ 6x1/2 =4, i,e 8 atoms each with a contribution of 1/8 present in the corners and 6 atom each with a contribution of 1/2 at the edges]
The F^- ions occupy the tetrahedral holes which are twice that of octahedral holes = 2 x 4 =8
Thus there are 8 F- present in the CaF₂ crystal.

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