Q47. A train travelled distance of 10 km, 20 km and 30 km at speed of 50 km, 60 km and 90 km per hour respectively. The average speed of the train (in km/hour) was:

(a) 66.67

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(b) 26.67

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(d) 70.34

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Solution

The correct option is C
(c) 69.23

$A v e r a g e s p e e d = \frac{12 + 20 + 30}{\frac{10}{50} + \frac{20}{60} + \frac{30}{90}} = \frac{60}{\frac{1}{5} + \frac{1}{3} + \frac{1}{3}} = \frac{60}{\frac{1}{5} + \frac{2}{3}} = \frac{60}{\frac{3 + 10}{15}} = \frac{60}{\frac{13}{15}} = 69.23 k m / h r$

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Q47. A train travelled distance of 10 km, 20 km and 30 km at speed of 50 km, 60 km and 90 km per hour respectively. The average speed of the train (in km/hour) was:

The correct option is C (c) 69.23 Average speed =12+20+301050+2060+3090=6015+13+13=6015+23=603+1015=601315=69.23km/hr

The correct option is C
(c) 69.23

$A v e r a g e s p e e d = \frac{12 + 20 + 30}{\frac{10}{50} + \frac{20}{60} + \frac{30}{90}} = \frac{60}{\frac{1}{5} + \frac{1}{3} + \frac{1}{3}} = \frac{60}{\frac{1}{5} + \frac{2}{3}} = \frac{60}{\frac{3 + 10}{15}} = \frac{60}{\frac{13}{15}} = 69.23 k m / h r$