Question

Q7) atoms of an element B forms HCP lattice and those of the elements A occupy 2/3rd of tetrahedral voids derive the formula of the compound

Answer 1

There are totla 6 atoms in hcp lattice... so B = 6

Now , tetrahedral voids will be = 2N = 2*6 = 12 But given , A = 2/3 * 2N = 2/3 * 12 = 8

hence , A = 8 & B=6

so Formula of the compound = A8B6 = A4B3