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Question

4FeS+7O22Fe2O3+4SO2
Cr2O27+2H++3SO22Cr3++3SO24+H2O
1 g sample of FeS was roasted with oxygen gas SO2 thus formed required 10 mL of 0.05 M K2Cr2O7 solution in acidic medium. Calculate percentage of FeS in the sample. (Fe=56,S=32)

A
1.2%
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B
1.32%
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C
1.5%
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D
None of these
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Solution

The correct option is B 1.32%
10 mL of 0.05 M K2Cr2O7=10×0.051000 mol=5×104 mol
SO2=3×5×104 mol
pure FeS=3×5×104 mol
=15×104×88 g
=0.132 g in 10g impure FeS
=1.32%

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