4FeS+7O2⟶2Fe2O3+4SO2 Cr2O2−7+2H++3SO2⟶2Cr3++3SO2−4+H2O 1g sample of FeS was roasted with oxygen gas SO2 thus formed required 10mL of 0.05MK2Cr2O7 solution in acidic medium. Calculate percentage of FeS in the sample. (Fe=56,S=32)
A
1.2%
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B
1.32%
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C
1.5%
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D
None of these
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Solution
The correct option is B1.32% 10mL of 0.05MK2Cr2O7=10×0.051000mol=5×10−4mol SO2=3×5×10−4mol pureFeS=3×5×10−4mol =15×10−4×88g =0.132 g in 10g impure FeS =1.32%