Quality factor of series resonance circuit is given by

\frac{f_{2} - f_{1}}{f_{0}}

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f_{2} - f_{1}

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\frac{f_{1} - f_{0}}{f_{2}}

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\frac{f_{0}}{f_{2} - f_{1}}

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Solution

The correct option is B $\frac{f_{0}}{f_{2} - f_{1}}$
Quality factor is a relation between stored energy and energy dissipation in
a device or system.
As per definition of Quality factor:
$Q_{f a c t o r} = \frac{F_{0}}{B W} .$

Where $B W = f_{2} - f_{1}$ bandwidth. Here $f_{2}$ and $f_{1}$ are half power
frequencies.

Therefore option D is correct.

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Similar questions

f (x) = 2^{x}

f (0), f (1), f (2) . . . . .

f_{1}

f_{2}

f_{0}

= l + (\frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}}) \times h

∣ ∣ ∣_{1} \times_{2} ∣ ∣ ∣ =_{1} ._{2}

∣ ∣ ∣_{1} +_{2} ∣ ∣ ∣

The h in the formula

Mode=I+ $(\frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}})$ $\times$ h

stands for class width.

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