Question

Ques) In a city the corporation supplies water to 35 houses in a street through a cylindrical tank of radius 42 cm and height 105 cm.On a particular day due to leakage in the tank, water was sufficient only 25 houses. The people in the street told the supplier to distribute the available water to the 35 houses. Find ,
(i) how much water each house gets on any day ?
(ii) how much water each house gets on the day when there was leakage in the tank ?
(iii) what values the people in the street possess ?

Answer 1

Dear student
$$\begin{gathered} Volumeofcylinder={\mathrm{\pi r}}^2\mathrm{h} \\ \mathrm{Where}\mathrm{r}=42\mathrm{cm}\mathrm{and}\mathrm{height}=105\mathrm{cm} \\ \mathrm{So},\mathrm{volume}=\frac{22}{7}\times {42}^2\times 105=582120{\mathrm{cm}}^3 \\ \mathrm{Share}\mathrm{of}35\mathrm{houses}\mathrm{without}\mathrm{any}\mathrm{leakage}=\frac{\mathrm{Volume}\mathrm{of}\mathrm{cylinder}}{35}=\frac{582120}{35}=16632{\mathrm{cm}}^3 \\ \mathrm{Share}\mathrm{of}25\mathrm{houses}\mathrm{with}\mathrm{leakage}=\frac{\mathrm{Volume}\mathrm{of}\mathrm{cylinder}}{25}=\frac{582120}{25}=23284.8{\mathrm{cm}}^3 \\ \mathrm{Total}\mathrm{leakage}=25\times \left(\mathrm{Share}\mathrm{of}25\mathrm{houses}\mathrm{with}\mathrm{leakage}-\mathrm{Share}\mathrm{of}35\mathrm{houses}\mathrm{without}\mathrm{leakage}\right) \\ =166320{\mathrm{cm}}^3 \\ \mathrm{Water}\mathrm{available}\mathrm{after}\mathrm{leakage}=\mathrm{Total}\mathrm{water}-\mathrm{Total}\mathrm{leakage}=415800{\mathrm{cm}}^3 \\ \mathrm{Now}\mathrm{share}\mathrm{of}35\mathrm{houses}\mathrm{after}\mathrm{leakage}=\frac{415800}{35}=11880{\mathrm{cm}}^3 \\ \mathrm{The}\mathrm{value}\mathrm{people}\mathrm{possess}\mathrm{is} \\ \mathrm{sharing} \\ \mathrm{caring} \\ \mathrm{responsible}\mathrm{citizen} \end{gathered}$$
Regards