A housing society consisting of $5500$ people needs $100$ litres of water per person per day. The cylindrical supply tank is $7 m$ high and has a diameter $10 m$ . For how many days will the water in the tank last for the society members?

1

day

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2

days

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3

days

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4

days

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Solution

The correct option is B $1$ day
Quantity of water required for $5500$ people for 1 day $= 5500 \times 100 = 550000 l i t r e s$
Volume of cylindrical supply tank $= π r^{2} h = \frac{22}{7} \times 5 \times 5 \times 7 = 550 m^{3} = 550, 000 l i t r e s$
Number of days $= \frac{550000}{550000} = 1 d a y$

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A housing society consisting of $5500$ people needs $100 L$ of water per person per day. The cylindrical supply tank is $7 m$ high and has a diameter $10 m$ . For how many days will the water in the tank last for the society?

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A housing society consisting of 5500 people needs 100 litres of water per person per day. The cylindrical supply tank is 7m high and has a diameter 10m. For how many days will the water in the tank last for the society members?

The correct option is B 1 dayQuantity of water required for 5500 people for 1 day =5500×100=550000litresVolume of cylindrical supply tank =πr2h=227×5×5×7=550m3=550,000litresNumber of days =550000550000=1day

A housing society consisting of $5500$ people needs $100$ litres of water per person per day. The cylindrical supply tank is $7 m$ high and has a diameter $10 m$ . For how many days will the water in the tank last for the society members?