Question 1(i)
Evaluate:

$3^{- 2}$

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Solution

$3^{- 2} = \frac{1}{3^{2}} [∵ a^{- m} = \frac{1}{a^{m}}] = \frac{1}{9}$

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Similar questions

Question 1(i) :

Solve:

$\frac{2}{3} + \frac{3}{4} + \frac{1}{2}$

Question 180(ii)

Simplify

${[{(\frac{4}{3})}^{- 2} - {(\frac{3}{4})}^{2}]}^{- 2}$

\frac{3 t - 2}{4} - \frac{2 t + 3}{3} = \frac{2}{3} - t

Question 2 (ii)
Simplify $(3 + \sqrt{3}) (3 - \sqrt{3})$ .

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