Question 1(i)
Multiply the binomials:
(2x+5) and ( 4x-3)

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Solution

$(2 x + 5) \times (4 x - 3) = 2 x (4 x - 3) + 5 (4 x - 3)$
$= 2 x \times 4 x - 2 x \times 3 + 5 \times 4 x - 5 \times 3$
$= 8 x^{2} - 6 x + 20 x - 15$
$= 8 x^{2} + 14 x - 15$

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Question 51

Solve the following:

$\frac{2 x - 3}{4 x + 5} = \frac{1}{3}$

Question 51

Solve the following:

$\frac{2 x - 3}{4 x + 5} = \frac{1}{3}$

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