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Solution of an Equation

Question 51So...

Question

Question 51

Solve the following:

$\frac{2 x - 3}{4 x + 5} = \frac{1}{3}$

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Solution

Given, $\frac{2 x - 3}{4 x + 5} = \frac{1}{3} \Rightarrow 3 (2 x - 3) = 4 x + 5 \Rightarrow 6 x - 9 = 4 x + 5 \Rightarrow 6 x - 4 x = 9 + 5 \Rightarrow 2 x = 14 \Rightarrow \frac{2 x}{2} = \frac{14}{2} ∴ x = 7$

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Similar questions

Question 51

Solve the following:

$\frac{2 x - 3}{4 x + 5} = \frac{1}{3}$

Question 65

Solve the following:

$\frac{2 x - 1}{5} = \frac{3 x + 1}{3}$

Q. Question 16
The factorization of

4 x^{2} + 8 x + 3

(x + 1) (x + 3)

(2 x + 1) (2 x + 3)

(2 x + 2) (2 x + 5)

(2 x - 1) (2 x - 3)

Q. Question 1(i)
Multiply the binomials:
(2x+5) and ( 4x-3)

Question 2
Which of the following is not a quadratic equation?
(a) $2 (x - 1)^{2} = 4 x^{2} - 2 x + 1$
(b) $2 x - x^{2} = x^{2} + 5$
(c) ${(\sqrt{2} x + \sqrt{3})}^{2} = 3 x^{2} - 5 x$
(d) $(x^{2} + 2 x)^{2} = x^{4} + 3 + 4 x^{3}$

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Solution of an Equation

Standard VI Mathematics

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