wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Question 1
The ages of two friends Ani and Biju differ by 3 years. Ani’s father Dharam is twice as old as Ani and Biju is twice as old as his sister Cathy. The ages of Cathy and Dharam differs by 30 years. Find the ages of Ani and Biju.


Open in App
Solution

The difference between the ages of Biju and Ani is 3 years. Either Biju is 3 years older than Ani or Ani is 3 years older than Biju. However, it is obvious that in both cases, Ani’s father’s age will be 30 years more than that of Cathy’s age.
Let the age of Ani and Biju be x and y years respectively.
Therefore, age of Ani’s father, Dharam = 2 × x = 2x years
And age of Biju’s sister Cathy = y2 years
By using the information given in the question,
Case (I) When Ani is older than Biju by 3 years,
x - y = 3 (i)
2xy2=30
4x - y = 60 (ii)
Subtracting (i) from (ii), we obtain
3x = 60 - 3 = 57
x=573=19
Therefore, age of Ani = 19 years
And age of Biju = 19 - 3 = 16 years
Case (II) When Biju is older than Ani,
y - x = 3 (i)
2xy2=30
4x − y = 60 (ii)
Adding (i) and (ii), we obtain
3x = 63
x = 21
Therefore, age of Ani = 21 years
And age of Biju = 21 + 3 = 24 years


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon