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Factorization of a Quadratic Trinomial

Question 1viF...

Question

Question 1(vi)
Factorise the following expressions
$121 b^{2} - 88 b c + 16 c^{2}$

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Solution

$121 b^{2} - 88 b c + 16 c^{2} = (11 b)^{2} - 2 (11 b) (4 c) + (4 c)^{2} = (11 b - 4 c)^{2} [(a - b)^{2} = a^{2} - 2 a b + b^{2}]$

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Q. Question 1(vi)
Factorise the following expressions

121 b^{2} - 88 b c + 16 c^{2}

121 b^{2} - 88 b c + 16 c^{2}

121 b^{2} + 88 b c + 16 c^{2}

Q. Factorise the following expressions.
(i)

a^{2} + 8 a + 16

p^{2} - 10 p + 25

25 m^{2} + 30 m + 9

49 y^{2} + 84 y z + 36 z^{2}

4 x^{2} - 8 x + 4

121 b^{2} - 88 b c + 16 c^{2}

(l + m)^{2} - 4 l m

a^{4} + 2 a^{2} b^{2} + b^{4}

Q. Factorize each of the following expression:
(2a − b)² − 16c²

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Factorization of a Quadratic Trinomial

Standard VIII Mathematics

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