Question 105

A swimming pool is $200 m \times 50 m$ and has an average depth of 2m. By the end of a summer day, the water level drops by 2 cm. How many cubic metres of water is lost on the day?

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Solution

Dimensions of swimming pool are $200 m \times 50 m$
Average depth of the swimming pool = 2 m
At the end of summer day the water level drops by 2 cm
Volume of water in swimming pool $= L e n g t h \times B r e a d t h \times D e p t h$
$= 200 \times 50 \times 2 = 20000 m^{3}$
If water level drops by 2 cm it means new level of water
$= (2 - \frac{2}{100}) m = 198 m$ $[1 c m = \frac{1}{100} m]$
Volume of water after summer day $= 200 \times 50 \times 198 = 19800 m^{3}$
So water in cubic metres was lost on that day
= Initial volume - Volume after summer day
$= 20000 - 19800 = 200 m^{3}$

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Question 105 A swimming pool is 200 m×50 m and has an average depth of 2m. By the end of a summer day, the water level drops by 2 cm. How many cubic metres of water is lost on the day?

Question 105

A swimming pool is $200 m \times 50 m$ and has an average depth of 2m. By the end of a summer day, the water level drops by 2 cm. How many cubic metres of water is lost on the day?