Question

Question 11
Eleven bags of wheat flour, each marked 5kg, actually contained the following weights of flour (in kg):
4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 4.98, 5.04,5.07, 5.00
Find the probability that any of these bags chosen at random contains more than 5 Kg of flour.

Answer 1

Number of total bags = 11
Number of bags containing more than 5 kg of flour =7

$\text{P(bags chosen at random contains more than 5kg of flour)}=\frac{\text{Number of bags containing more than 5kg of flour}}{\text{Number of total bags}}$
Hence, required probability, $P=\frac{7}{11}$