Figures on the Same Base and Between the Same Parallels
Question 11 i...
Question
Question 11 (ii) In the given figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that: (ii) ar(AEDF) = ar(ABCDE)
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Solution
It can be observed that, Area(ΔACB)=Area(ΔACF)
Then, Area(ΔACB)+Area(ACDE)=Area(ACF)+Area(ACDE)
[Adding Area(ACDE) on both sides] ⇒ Area(ABCDE) = Area(AEDF)