Question 11
The average atomic mass of a sample of an element X is 16.2u. What are the percentages of isotopes 168X and 188X in the sample?
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Solution
Let the percentage of 168X be A
Then the percentage of 188X=100−A
Then we have 16×A100+((100−A)×18)100=16.2 Or,1800−1620=18A−16A A=90 168X is 90% and is 188X is 10%.