Question

Question 12 (i)
In Fig. 12.30, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm, find the area of the
(i) quadrant OACB

Answer 1

Radius of the quadrant $=3.5cm=\frac{7}{2}cm$
Area of quadrant = $\frac{\left(\pi R^2\right)}{4}c{m}^2$
$=\frac{(\frac{22}{7}\times \frac{7}{2}\times \frac{7}{2})}{4}c{m}^2$
$=\frac{77}{8}c{m}^2$