Question 16
The factorization of $4 x^{2} + 8 x + 3$ is

A) $(x + 1) (x + 3)$
B) $(2 x + 1) (2 x + 3)$
C) $(2 x + 2) (2 x + 5)$
D) $(2 x - 1) (2 x - 3)$

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Solution

The answer is B.
$4 x^{2} + 8 x + 3 = 4 x^{2} + 6 x + 2 x + 3$ [by splitting middle term]
$= 2 x (2 x + 3) + 1 (2 x + 3)$
$= (2 x + 3) (2 x + 1)$

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