Question 1940a 20b 16 c 140d 64

40 = 40/100×[100 20/100× 300 ] =40/100[100 60] =40/100× 40 = 4 × 4 = 16 ...

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Converting Fractions/Decimals to Percentages

Question 1940...

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Question 19

40% of [100 - 20% of 300] is equal to
(a) 20
(b) 16
(c) 140
(d) 64

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Question 19

40% of [100 - 20% of 300] is equal to
(a) 20
(b) 16
(c) 140
(d) 64

$\sqrt[3]{125 \times 64}$ = ?
(a) 100 (b) 40
(c) 20 (d) 30

Question 40

In $Δ A B C$ , $∠ A = 100^{\circ}$ , AD bisects $∠ A$ and $A D ⊥ B C$ . Then, $∠ B$ is equal to

a) $80^{\circ}$
b) $20^{\circ}$
c) $40^{\circ}$
d) $30^{\circ}$

140^{\circ}, 40^{\circ}, 20^{\circ}, 160^{\circ}

270^{\circ}, 150^{\circ}, 30^{\circ}, 20^{\circ}

40^{\circ}, 70^{\circ}, 90^{\circ}, 60^{\circ}

110^{\circ}, 40^{\circ}, 30^{\circ}, 180^{\circ}

Question 25
Sum of the number of primes between 16 to 80 and 90 to 100 is

(A) 20
(B) 18
(C) 17
(D) 16

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