Question 2 (ii)
Find the sums given below
(ii) 34 + 32 + 30 + ……….. + 10

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Solution

$34 + 32 + 30 + \dots \dots + 10 F o r t h i s A . P, a = 34 d = a_{2} - a_{1} = 32 - 34 = - 2 a_{n} = 10 L e t 10 b e t h e n^{t h} t e r m o f t h i s A . P . a_{n} = a + (n - 1) d 10 = 34 + (n - 1) (- 2) 12 = n - 1 n = 13 S_{n} = \frac{n}{2} (a + a_{n}) = \frac{13}{2} (34 + 10) = (13 \times \frac{44}{2}) = 13 \times 22 = 286$

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