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Negation of a Number

Question 2vWr...

Question

Question 2(v)
Write the additive inverse of each of the following:
$\frac{19}{- 6}$

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Solution

We know that additive inverse of a rational number
$\frac{a}{b} i s (\frac{- a}{b}), s u c h t h a t \frac{a}{b} + (\frac{- a}{b}) = 0$
Additive inverse of
$\frac{19}{- 6}$ is $\frac{19}{6}$ .

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Similar questions

Q. Question 2(iii)
Write the additive inverse of each of the following:

\frac{- 6}{- 5}

Q. Question 2(i)
Write the additive inverse of each of the following:

\frac{2}{8}

Write the additive inverse of each of the following:

(i) (ii) (iii) (iv) (v)

Question 9
The additive inverse of $\frac{- 7}{19}$ is:
(a) $\frac{- 7}{19}$
(b) $\frac{7}{19}$
(c) $\frac{19}{7}$
(d) $\frac{- 19}{7}$

Write the additive inverse of the following:
$\frac{2}{8}$

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Negation of a Number

Standard VII Mathematics

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